X^2+2x=3024

Solution for X^2+2x=3024 equation:

X^2+2X=3024

We move all terms to the left:

X^2+2X-(3024)=0

a = 1; b = 2; c = -3024;
Δ = b2-4ac
Δ = 22-4·1·(-3024)
Δ = 12100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12100}=110$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-110}{2*1}=\frac{-112}{2}
=-56
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+110}{2*1}=\frac{108}{2}
=54
$